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10x^2=6.4
We move all terms to the left:
10x^2-(6.4)=0
We add all the numbers together, and all the variables
10x^2-6.4=0
a = 10; b = 0; c = -6.4;
Δ = b2-4ac
Δ = 02-4·10·(-6.4)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*10}=\frac{-16}{20} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*10}=\frac{16}{20} =4/5 $
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